.VCSUB STA V+1 \ Set the low byte of V(1 0) to A, so now V(1 0) = (A V) LDY #2 \ K3(2 1 0) = (x_sign x_hi x_lo) - x-coordinate in data JSR TAS1 \ block at V(1 0) LDY #5 \ K3(5 4 3) = (y_sign y_hi z_lo) - y-coordinate of data JSR TAS1 \ block at V(1 0) LDY #8 \ Fall through into TAS1 to calculate the final result: \ \ K3(8 7 6) = (z_sign z_hi z_lo) - z-coordinate of data \ block at V(1 0)Name: VCSUB [Show more] Type: Subroutine Category: Maths (Arithmetic) Summary: Calculate vector K3(8 0) = [x y z] - coordinates in (A V)Context: See this subroutine in context in the source code References: This subroutine is called as follows: * TACTICS (Part 1 of 7) calls VCSUB

Calculate the following: K3(2 1 0) = (x_sign x_hi x_lo) - x-coordinate in (A V) K3(5 4 3) = (y_sign y_hi z_lo) - y-coordinate in (A V) K3(8 7 6) = (z_sign z_hi z_lo) - z-coordinate in (A V) where the first coordinate is from the ship data block in INWK, and the second coordinate is from the ship data block pointed to by (A V).

[X]

Subroutine TAS1 (category: Maths (Arithmetic))

Calculate K3 = (x_sign x_hi x_lo) - V(1 0)