Calculate the following division and remainder:
P = DELTA / (the Y-th stardust particle's z_hi coordinate)
R = remainder as a fraction of A, where 1.0 = 255
Another way of saying the above is this:
(P R) = 256 * DELTA / z_hi
DELTA is a value between 1 and 40, and the minimum z_hi is 16 (dust particles
are removed at lower values than this), so this means P is between 0 and 2
(as 40 / 16 = 2.5, so the maximum result is P = 2 and R = 128.
This uses the same shift-and-subtract algorithm as TIS2, but this time we
keep the remainder.
Arguments:YThe number of the stardust particle to process Returns:C flagThe C flag is cleared
.DV42LDASZ,Y\ Fetch the Y-th dust particle's z_hi coordinate into A\ Fall through into DV41 to do:\\ (P R) = 256 * DELTA / A\ = 256 * DELTA / Y-th stardust particle's z_hi